A pendulum with a period of 1 s on Earth, where the acceleration due to gravity is g, is taken to another planet, where its period is 2s. The acceleration due to gravity on the other planet is most nearly (A) g/4
Full Answer
What length of pendulum has a period of 1's on earth?
Answer and Explanation: Answer: 0.248 m length of pendulum will produce a period 1.0 s. Explanation: Given: Time period T=1.0 s.
What is the length of a simple pendulum with a period of 1 s?
about 0.249mHere's my guess: a simple pendulum with period 1.00s has a length of about 0.249m.
What is the period of a pendulum with a length of 1m?
2 secondSolution : The time period of a simple pendulum of length 1 m is 2 second.
What is the period in seconds of a simple pendulum?
two secondsA seconds pendulum is a pendulum whose period is precisely two seconds; one second for a swing in one direction and one second for the return swing, a frequency of 0.5 Hz.
How do I calculate the length of a pendulum?
To calculate the length of a simple pendulum, use the formula L = (T/ 2π)²*g . Where T is the time period of the simple pendulum and g is the acceleration due to gravity.
How do you use a pendulum formula?
Pendulums are used to regulate the movement of clocks because the interval of time for each complete oscillation, called the period, is constant. The formula for the period T of a pendulum is T = 2π Square root of√L/g, where L is the length of the pendulum and g is the acceleration due to gravity.
What is the period on Earth of pendulum with a length of 1.0 m?
2.01 secondsWe are asked to find the period of a 1.00 meter long simple pendulum. So the formula for period is 2π times the square root of the length of the pendulum divided by acceleration due to gravity. So that's 2π times square root of 1.00 meter divided by 9.80 meters per second squared which is 2.01 seconds.
How do u calculate period?
To calculate your menstrual cycle, count the days between your last few periods. Begin counting on the first day of your period to the day before your next period.Do this for a few cycles, and add up the total number of days, dividing it by the number of cycles.
What is the period of a 3.5 m long pendulum on Earth?
3.749 sThe time period is given by: Tn=2π√Lgn=2π√3.59.832=3.749 s.
What is the length of simple pendulum on earth surface whose period is 1 second?
1mThe length of a seconds pendulum on the surface of the earth is 1m.
What is the length of seconds pendulum on earth?
1 m.The length of a second pendulum at the surface of earth is 1 m. The length of second pendulum at the surface of moon, where g is 16th that of earth's surface.
How do you find the length of a seconds pendulum?
On earth, the seconds pendulum has a constant length of approximately 1m. Q. The length of a second pendulum is 1m [ where g=9.8m/s2].
What length of string is needed so a simple pendulum could have a frequency of 1.0 Hz?
Frequency. For example, the length of a pendulum that would have a frequency of 1 Hz (1 cycle per second) is about 0.25 meters.
What is the length of a pendulum that has a period of 0.500 s?
approximately 0.062mThus, the length of the pendulum is approximately 0.062m .
What will be the frequency of simple pendulum if its length is 1m?
A simple pendulum of length 1 m is oscillating with an angular frequency 10 rad/s.
What is the period of a 1.4 m pendulum?
Now the length of the pendulum given is 1.4 m, and the gravitational acceleration is 9.8 m per second square. Now substitute the value to find out the period of oscillation that is two times 3.14 Times squirreled off 1.4 m over 9.8 m per second squared, Or the bill of oscillation for the pendulum has 2.4 seconds.